4y^2-19y-5=0

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Solution for 4y^2-19y-5=0 equation:


Simplifying
4y2 + -19y + -5 = 0

Reorder the terms:
-5 + -19y + 4y2 = 0

Solving
-5 + -19y + 4y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-1 + -4y)(5 + -1y) = 0

Subproblem 1

Set the factor '(-1 + -4y)' equal to zero and attempt to solve: Simplifying -1 + -4y = 0 Solving -1 + -4y = 0 Move all terms containing y to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -4y = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -4y = 0 + 1 -4y = 0 + 1 Combine like terms: 0 + 1 = 1 -4y = 1 Divide each side by '-4'. y = -0.25 Simplifying y = -0.25

Subproblem 2

Set the factor '(5 + -1y)' equal to zero and attempt to solve: Simplifying 5 + -1y = 0 Solving 5 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1y = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1y = 0 + -5 -1y = 0 + -5 Combine like terms: 0 + -5 = -5 -1y = -5 Divide each side by '-1'. y = 5 Simplifying y = 5

Solution

y = {-0.25, 5}

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